A complete binary tree has odd number of nodes .
Number of leaves + number of internal nodes ( both even) +
1 = number of nodes in a tree
The number of internal nodes + 1 = number of leaves
number of internal nodes = number of leaves - 1
n = number of nodes
n = number of leaves + number of internal nodes
n +1 = 2 * number of leaves
number of leaves = (n+1)/2
The number of total nodes upto height h :
= pow(2,h+1) - 1
The number of nodes for any binary tree at height (h) :
= ceil(n / pow(2,h+1))
Friday, January 25, 2008
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